THIS IS HOW MY URL.PY LOOKS LIKE
from django.conf.urls.defaults import *
from it.view import current_datetime
# Uncomment the next two lines to enable the admin:
#from django.contrib import admin
#admin.autodiscover()
urlpatterns = patterns('',
# Example:
(r"^wap/di/sub/$",current_datetime),
# Uncomment the admin/doc line below to enable admin documentation:
# (r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
# (r'^admin/', include(admin.site.urls)),
)
`~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
My view .py looks like this
from django.http import *
import urllib
from django_restapi.responder import XMLResponder
def current_datetime(request):
word = request.GET['word']
message =
urllib.urlopen('http://m.broov.com/wap/di/sub?word='+word+'&type=00submit=Submit',)
return XMLResponder(message)
But my error is
Exception Value:
'XMLResponder' object has no attribute 'status_code'
Exception Location:
D:\Python25\lib\site-packages\django\middleware\common.py in
process_response, line 94
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