On Tue, Nov 2, 2010 at 10:42 PM, wawa wawawa <wazawaz...@gmail.com> wrote:
> Hi All, > > So, I've got my django app, rabbitmq and celery working and processing > my uploaded files. Next step is to get the client to display status > results provided by JSON, ultimately refreshing to a results page when > complete. > > I'm a little new to JSON / AJAX (AJAJ!) and I'm struggling a little > with the templates and views part. > > Are there any easy examples out there? > > Is the expectation like user will upload a file and will see a result? if that is case why are using celery? b-list has a ajax example[1]. BTW, if you are trying to upload a file using ajax you need to create iframe using javascript, you might want to use jsupload[2] [1] http://www.b-list.org/weblog/2006/jul/31/django-tips-simple-ajax-example-part-1/ [2] http://valums.com/ -- regards, Prashanth twitter: munichlinux blog: honeycode.in irc: munichlinux, JSLint, munichpython. -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.