Just have my_fnc return a dictionary (or other object), rather than the
whole rendered response:
def search(request):
..........
answ = my_fnc(roots)
return render_to_response("my_fnc.html", { "answ" : answ['FindWord'] } )
def my_fnc( roots ):
FindWord=authors.objects.filter("name"__contains=roots)
return { "FindWord" : FindWord }
(A couple of style points:
- PEP8 recommends avoiding CamelCase in favour of under_scores
- In views.py, I lean towards naming functions that aren't views, (my_fnc
in this case) with an underscore, such as _my_fnc)
)
Hope this helps,
Greg
On 3 January 2011 20:45, gintare <g.statk...@gmail.com> wrote:
>
> How formulate correctly the code below:
>
> [code]
> #views.py
>
> def search(request):
> ..........
> answ = my_fnc(roots)
> return render_to_response("my_fnc.html", { "answ" : answ } )
>
> def my_fnc( roots ):
> FindWord=authors.objects.filter("name"__contains=roots)
> return render_to_response("my_fnc.html", { " FindWord" :
> FindWord } )
>
> [code]
>
> Gives error Manager isn't accessible via FindWord instances
>
> I would like to get result of quesry in separate function.
> How to return this result to initial function in view or print it to
> *.html form from another function?
>
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--
Dr Greg Turner
Director, the Interaction Consortium
http://interaction.net.au
Phone: +61 2 8060 1067
skype: gregturner
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