Thanks On Jan 7, 9:27 am, Chris Matthews <[email protected]> wrote: > {% for Ltarp in smth.3 %} > SHOULD BE > {% for Ltarp in smth.2 %} > 'cos Lans only has 3 elements and Ltarp is Lans[2]. > > Chris > > -----Original Message----- > From: [email protected] [mailto:[email protected]] On > Behalf Ofgintare > Sent: 07 January 2011 08:52 > To: Django users > Subject: list of lists in template > > in view.py > ... > Ltarp.append([item.Wordword, item.WordTranslEn, item.WordNotesGram, > item.WordConcl]) > .. > Lans.append([sen.Sent, sen.SentTransl, Ltarp ] ) > > in template.html > {% if Lans %} > > {% for smth in Lans %} > <table > > <tr> <td width='500'> {{smth.0}} </td></tr> > > {% for Ltarp in smth.3 %} > <tr> > <td width='500'> {{Ltarp.0}} </td> > > </tr> > {% endfor %} > > </table> > {% endfor %} > > {% endif %} > > ########################### > > the rows from smth.0 are shown > the rows from Ltarp in smth.3, i.e. {{Ltarp.0}} are not shown. > > I tried also:Ltarp, Ltarp[0], smth.Ltarp.0 > > nothing works in the second for cycle where i need to get items from > list built in third item of list in the first for cycle. > > Could you please help with syntax, when i need to dislay item from > list in another list in template > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group > athttp://groups.google.com/group/django-users?hl=en.
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