Thanks

On Jan 7, 9:27 am, Chris Matthews <[email protected]> wrote:
> {%  for Ltarp in  smth.3 %}
> SHOULD BE
> {%  for Ltarp in  smth.2 %}
> 'cos Lans only has 3 elements and Ltarp is Lans[2].
>
> Chris
>
> -----Original Message-----
> From: [email protected] [mailto:[email protected]] On 
> Behalf Ofgintare
> Sent: 07 January 2011 08:52
> To: Django users
> Subject: list of lists in template
>
> in view.py
> ...
> Ltarp.append([item.Wordword, item.WordTranslEn, item.WordNotesGram,
> item.WordConcl])
> ..
> Lans.append([sen.Sent, sen.SentTransl, Ltarp ] )
>
> in template.html
> {% if Lans %}
>
> {%  for smth in Lans %}
> <table >
> <tr> <td width='500'> {{smth.0}} </td></tr>
>
>     {%  for Ltarp in  smth.3 %}
>     <tr>
>     <td width='500'> {{Ltarp.0}} </td>
>
>     </tr>
>     {% endfor %}
>
> </table>
> {% endfor %}
>
> {% endif %}
>
> ###########################
>
> the rows from smth.0 are shown
> the rows from  Ltarp in  smth.3, i.e. {{Ltarp.0}} are not shown.
>
> I tried also:Ltarp, Ltarp[0], smth.Ltarp.0
>
> nothing works in the second for cycle where i need to get items from
> list built in third item of list in the first for cycle.
>
> Could you please help with syntax, when i need to dislay item from
> list in another list in template
>
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