The book "The definitive Guide to Django" says on page 476:
---8<---
... if you want to override the 404 view, you can specify 'handler404' in your
URLconf, like so:
from django.conf.urls.defaults import *
urlpatterns = patterns ('',
...
)
handler404 = 'mysite.views.my_custom_404_view'
Behind the scenes ...
---8<---
hope this helps,
good luck,
TR
Am 18.01.2011 um 13:42 schrieb Ivo Brodien:
> I guess that django catches the 404 Error Code somehow somewhere else than in
> the handler? Maybe you have to set the HTTP Code to 200?
>
>
> On 18.01.2011, at 13:35, galago wrote:
>
>> Yes I have a index pattern:
>> urlpatterns = patterns('',
>> url(r'^$', 'index.views.index', name='index'),.......
>>
>> When I add print to my method:
>> def custom404(request):
>> print 'foo'
>> return HttpResponseRedirect(reverse('index'))
>>
>> It prints out but it doesn't redirect me to index. Instead it displays my
>> 404.html page.
>>
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