Do you want the episode with the highest individual score, or the
highest average score?

Alex

On Thu, Feb 10, 2011 at 7:41 AM, Andres Lucena <andresluc...@gmail.com> wrote:
> On Thu, Feb 10, 2011 at 2:29 PM, Alex Robbins
> <alexander.j.robb...@gmail.com> wrote:
>> Yeah, you'll definitely want to find some aggregate to do the sorting.
>
> Ok, didn't know it. I'll take a look at it...
>
>> The only way to sort by a custom method is doing an in-python sort,
>> which is going to be much slower than having the db sort for you.
>
> Yeah, I tought so but it seems (to me) the only way of doing this...
>
>>  If you post the score models, we could probably help more.
>
> The score models are from django-voting:
>
> http://django-voting.googlecode.com/svn/trunk/voting/models.py
> http://django-voting.googlecode.com/svn/trunk/voting/managers.py
>
> Thanks for the help!
>
> Andres
>
>
>>
>> Alex
>>
>> On Feb 9, 8:49 am, "Casey S. Greene" <csgre...@princeton.edu> wrote:
>>> I haven't used django-voting but it sounds to me like you want something
>>> like:
>>> Link.objects.aggregate(Avg(score = 'vote__score')).order_by('score')
>>>
>>> If I recall correctly you can chain aggregate and order_by.
>>>
>>> Anyway, that example and this link should get you started at 
>>> least:http://docs.djangoproject.com/en/dev/topics/db/aggregation/
>>>
>>> Hope this helps!
>>> Casey
>>>
>>>
>>>
>>>
>>>
>>>
>>>
>>> On Wed, 2011-02-09 at 10:08 +0100, Andres Lucena wrote:
>>> > On Tue, Feb 8, 2011 at 6:00 PM, Andres Lucena <andresluc...@gmail.com> 
>>> > wrote:
>>> > > Dear Gurus,
>>>
>>> > > I've made a custom method for getting the score (from django-voting)
>>> > > for a giving Model:
>>>
>>> > > class Link(models.Model):
>>> > >    episode = models.ForeignKey("Episode", related_name="links")
>>> > >    url = models.CharField(max_length=255, unique=True, db_index=True)
>>>
>>> > >    def __unicode__(self):
>>> > >        return self.url
>>>
>>> > >    def get_score(self):
>>> > >        return Vote.objects.get_score(self)['score']
>>>
>>> > > Now I want to make a custom manager to getting the top-scored links
>>> > > for the given episode. AFAIK, you can't sort by a custom method, so
>>> > > I'm trying to apply the ordering through sorted(), like this links
>>> > > says:
>>>
>>> > >http://stackoverflow.com/questions/981375/using-a-django-custom-model...
>>> > >http://stackoverflow.com/questions/883575/custom-ordering-in-django
>>>
>>> > > So, what I have now is this:
>>>
>>> > > class LinkGetTopScores(models.Manager):
>>> > >    def get_top_score(self):
>>> > >        return sorted(self.filter(episode=self.episode), key=lambda n:
>>> > > n.get_score)
>>>
>>> > > class Link(models.Model):
>>> > >    episode = models.ForeignKey("Episode", related_name="links")
>>> > >    url = models.CharField(max_length=255, unique=True, db_index=True)
>>> > >    get_top_score = LinkGetTopScores()
>>> > > ....
>>>
>>> > > So of course this isn't working because of the self.episode stuff...
>>> > > But I've to filter somehow by episode (the ForeignKey), and I don't
>>> > > know how. Is there anyway of doing this?? What I'm doing is right or
>>> > > there would be an easier way of doing this?
>>>
>>> > I noticed that the .filter isn't necesary, so now I have this:
>>>
>>> > class LinkGetTopScores(models.Manager):
>>> >     def get_top_score(self):
>>> >         return sorted(self.all(), key=lambda n: n.get_score)
>>>
>>> > But it don't sort by score, and I don't know what I'm doing wrong :S
>>>
>>> > Any idea?
>>>
>>> > Thanks,
>>> > Andres
>>>
>>> > > Thank you,
>>> > > Andres
>>
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