I've been googling and trying this for 2 days now, I'm sure I'm just
confused about something basic because it cannot be that hard. I've
tried all the hints I found via google and they made sense but no
success.
I'm running RHEL 6 Python 2.6.5, django 1.2.4 and mod_wsgi 3.2. I'm
trying to configure the server so I can deploy independent django sites
via wsgi. So my directory structure looks like this:
/var/www/wsgi-scripts
-> myapp.wsgi
-> test2.wsgi
... such that I can drop in any wsgi file to deploy a new app.
I plan to deploy my django sites (totally independent of one another,
but all related to our intranet) as follows
/home/djangodeploy
-> __init__.py
-> mysite1
-> mysite2
________________________________________________________________
I got a basic myapp.wsgi working OK and it prints out sys.path as
follows:
/home/djangodeploy
/usr/lib/python26.zip
/usr/lib/python2.6
/usr/lib/python2.6/plat-linux2
...snip...
/usr/lib/python2.6/site-packages/webkit-1.0
________________________________________________________________
I've made sure apache is the user for all files and even changed
permissions to 777. I've remembered to restart apache each time. I
tried to import settings.py from the command line to make sure there
were no syntax errors and it works. This site worked under the debug
server also.
________________________________________________________________
My wsgi.conf file looks like this:
LoadModule wsgi_module modules/mod_wsgi.so
WSGIScriptAlias /wsgi /var/www/wsgi-scripts
WSGIPythonPath /home/djangodeploy
LogLevel info
WSGISocketPrefix /var/run/wsgi
<Directory /var/www/wsgi-scripts>
Order allow,deny
Allow from all
</Directory>
<Directory /home/djangodeploy> ### I'm not sure about this last
Directory, grasping at straws.
Order allow,deny
Allow from all
</Directory>
________________________________________________________
My wsgi module to launch django looks like this
import os, sys
print >>sys.stderr, __file__, sys.path
#import homeworks # this did not work
os.environ['DJANGO_SETTINGS_MODULE'] = 'homeworks.settings' #this did
not work
#never gets here
import django.core.handlers.wsgi
application = django.core.handlers.wsgi.WSGIHandler()
______________________________________________
And the output of the apache error log looks like this (timestamp and ip
deleted for brevity):
ImportError: Could not import settings 'homeworks.settings' (Is it on
sys.path? Does it have syntax errors?): No module named
homeworks.settings
/var/www/wsgi-scripts/test2.wsgi ['/home/djangodeploy',
'/usr/lib/python26.zip', '/usr/lib/python2.6',
'/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk',
'/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload',
'/usr/lib/python2.6/site-packages',
'/usr/lib/python2.6/site-packages/gst-0.10',
'/usr/lib/python2.6/site-packages/gtk-2.0',
'/usr/lib/python2.6/site-packages/webkit-1.0']
mod_wsgi (pid=2399): Exception occurred processing WSGI script
'/var/www/wsgi-scripts/test2.wsgi'.
Traceback (most recent call last):
File "/usr/lib/python2.6/site-packages/django/core/handlers/wsgi.py",
line 230, in __call__
self.load_middleware()
File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py",
line 33, in load_middleware
for middleware_path in settings.MIDDLEWARE_CLASSES:
File "/usr/lib/python2.6/site-packages/django/utils/functional.py",
line 276, in __getattr__
self._setup()
File "/usr/lib/python2.6/site-packages/django/conf/__init__.py", line
40, in _setup
self._wrapped = Settings(settings_module)
File "/usr/lib/python2.6/site-packages/django/conf/__init__.py", line
75, in __init__
raise ImportError("Could not import settings '%s' (Is it on
sys.path? Does it have syntax errors?): %s" % (self.SETTINGS_MODULE, e))
[Wed Mar 30 11:46:53 2011] [error] [client 192.168.218.34] ImportError:
Could not import settings 'homeworks.settings' (Is it on sys.path? Does
it have syntax errors?): No module named homeworks.settings
Would someone be kind enough to show me my mistake. I've tried all I
can think of.
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