I'm afraid I can't help you any further on this, as I don't know enough
about the contenttypes framework, and I still don't really understand what
it is you are asking.
Cal
I got it fixed . Now I have smaller issue . Foreign key ( of a particular
model) is returning me a table_id with some random integer value . How do I
use that to actually access the table .
As in , in another app , how do I know an integer 34 refers to a particular
row of the table from which the foreign key has been taken
Satyajit
On Fri, Jun 24, 2011 at 2:40 AM, Cal Leeming [Simplicity Media Ltd] <
cal.leem...@simplicitymedialtd.co.uk> wrote:
> Again, please keep your replies on-list.
>
> I'm afraid I can't help you any further on this, as I don't know enough
> about the contenttypes framework, and I still don't really understand what
> it is you are asking.
>
> Cal
>
>
> On Thu, Jun 23, 2011 at 10:07 PM, Satyajit Sarangi <
> writetosatya...@gmail.com> wrote:
>
>> I am not saying what is a query set error . I am saying , why am I getting
>> such an error , when in the documentation it is mentioned that the exact
>> query works .
>>
>> On Fri, Jun 24, 2011 at 2:35 AM, Cal Leeming [Simplicity Media Ltd] <
>> cal.leem...@simplicitymedialtd.co.uk> wrote:
>>
>>> Please keep your replies on-list so others may benefit in the future.
>>>
>>> On Thu, Jun 23, 2011 at 10:01 PM, Satyajit Sarangi <
>>> writetosatya...@gmail.com> wrote:
>>>
>>>> First of all , when I am doing this
>>>> perm.table =
>>>> ContentType.objects.get(app_label="OsmMap",model="Osm_Layers") I am getting
>>>> a content type matching query doesnt exist error .
>>>>
>>>
>>> I personally don't ever use the contenttypes framework (at least not
>>> directly), so I can't help you here.
>>>
>>>
>>>>
>>>> In another app , in its views . I have done this
>>>>
>>>> tab_id = 3
>>>> this_user = request.user
>>>> user1= this_user.pk
>>>> uperm = PermiLayer()
>>>> a=uperm.objects.get(user_id__exact=pk,table_id_exact=tab_id)
>>>> if a.permi == 3:
>>>> lcount = Osm_Layers()
>>>> lcount= Osm_Layers.objects.get(pk=tab_id)
>>>> form1 = ReadOnlyForm(initial={"geomcollection":
>>>> lcount.geom_poly})
>>>>
>>>>
>>>> What I am doing here is this , I am checking if the table_ id and the
>>>> user_id that has logged in has a certain permission . Permission can be any
>>>> number , and thus a certain user on a certain table can have 3 , 2 or/and 1
>>>> as permission . Thus it would repeat itself . Thus , how do I query the db
>>>> better than my present view . And also , what is the query set error?
>>>>
>>>
>>> If you are encountering any condition where data is repeating where it
>>> shouldn't, then I'd say there is a fault in your logic.
>>>
>>> Also, what do you mean by "what is the query set error"?
>>>
>>>
>>>>
>>>> On Fri, Jun 24, 2011 at 2:27 AM, Cal Leeming [Simplicity Media Ltd] <
>>>> cal.leem...@simplicitymedialtd.co.uk> wrote:
>>>>
>>>>> **
>>>>> You're going to have to explain this a lot better, because I really did
>>>>> not understand what you mean.
>>>>>
>>>>> At a *GUESS*, are you trying to prevent against db save race conditions
>>>>> or something??
>>>>>
>>>>> Please clarify.
>>>>>
>>>>> Cal
>>>>>
>>>>>
>>>>> On 23/06/2011 20:07, Satyajit Sarangi wrote:
>>>>>
>>>>> This is my models.py of a different app .
>>>>>
>>>>>
>>>>> class PermiLayer(models.Model):
>>>>> user = models.ForeignKey(User)
>>>>> table = models.ForeignKey(ContentType)
>>>>> permi = models.IntegerField()
>>>>>
>>>>>
>>>>> In another app's views , I am accessing a form that has given me a
>>>>> username .
>>>>>
>>>>> I have to check in PermiLayer model if the username along with the
>>>>> table id match in it and return back the data in permi .
>>>>>
>>>>> The problem here is , User + table can be present multiple times , as
>>>>> in the same user and and table id .
>>>>>
>>>>> What I am doing in my code is , do an object.get.all with a filter of
>>>>> the username and table id that I have on Permilayer . But ,
>>>>> object.get.all , as I have read , might just freeze my database , or
>>>>> slow it down considerably . Is there a faster/better way to do it ?
>>>>>
>>>>>
>>>>>
>>>>>
>>>>
>>>>
>>>> --
>>>> *Satyajit Sarangi*
>>>>
>>>>
>>>
>>
>>
>> --
>> *Satyajit Sarangi*
>>
>>
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