Hi guys,
I've been trying your suggestions but I'm afraid I'm stretching the
limits of my Python/Django abilities ;-)
Bruno got it right: what I want is a queryset of "model" with distinct
docid having the highest version number, sorted by revisiondate.
If have the following result of my
found_entries = model.objects.filter((Q-
objects),obsolete=0).order_by('-version','docid') :
+----+-------+---------+--------------+
| pk | docid | version | revisiondate |
+----+-------+---------+--------------+
| 1 | 1 | 1 | 2000-02-10 |
| 2 | 2 | 1 | 2000-02-11 |
| 3 | 3 | 1 | 2000-02-12 |
| 4 | 3 | 3 | 2000-02-13 |
| 5 | 2 | 3 | 2000-02-14 |
| 6 | 1 | 3 | 2000-02-15 |
+----+-------+---------+--------------+
Then I want to retrieve only these results, sorted on revisiondate:
+----+-------+---------+--------------+
| pk | docid | version | revisiondate |
+----+-------+---------+--------------+
| 6 | 1 | 3 | 2000-02-15 |
| 5 | 2 | 3 | 2000-02-14 |
| 4 | 3 | 3 | 2000-02-13 |
+----+-------+---------+--------------+
My code does this, but the loop that selects the distinct docid's is
what makes it terribly slow...
Hope this clarifies it.
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