Hi Jani
The def random_generator(n): here n parameter is any number which i will
get from my request in a function.
Now when i will get the number let say 101 i will pass this 101 in my
random_generator(n) so it becomes random_generator(101) .
Now in return it should give me 6-digit number. If the 101 comes again in
that function it will generate the same random number.
I read about random.seed but how can i relate that in my case.
Thanks for help.
On Wed, Mar 21, 2012 at 1:01 PM, Jani Tiainen <rede...@gmail.com> wrote:
> 21.3.2012 9:19, Nikhil Verma kirjoitti:
>
> Hi All
>>
>> I want to generate a fix 6-digit random number from a function.
>>
>> eg :-
>>
>> def random_generator(n):
>> # do domething great
>> return '6-digit random number'
>>
>> output examples
>> >>>random_number(6) # n is the input number that i will get from my
>> request
>> >>>987657
>>
>> >>>random_number(100)
>> >>>987647
>>
>> >>>random_number(6) # if the same input comes again it would generate a
>> same random number
>> >>>987657
>>
>> If the same input cannot be generated any other way to do this part
>>
>> Any help would be appreciated.
>>
>>
> It seems that you're initializing pseudorandom generator with same seed
> number. So yes, sequence of generated numbers will be same.
>
> so doing something like this:
>
> from random import choice # Initializes from current time.
>
> def random_digits():
> return [choice('0123456789') for i in range(7)]
>
> or if you need it:
>
> from random import randint # Initializes from current time.
>
> def random_int():
> return randit(100000, 999999)
>
>
> Note that pseudorandom generator is only initialized first time import
> happens. After that you can set it manually using
> random.seed([x]) function.
>
> --
>
> Jani Tiainen
>
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--
Regards
Nikhil Verma
+91-958-273-3156
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