seems like .html has another problem. it will duplicate itself (even not
seen in the screen).
but it did post Number of times when i submit the form. still need to
struggling..bugs still
exist..
On Sat, May 5, 2012 at 2:17 PM, Min Hong Tan <tan.dja...@gmail.com> wrote:
> hi Oscar,
>
> I think maybe it over some ajaxsetup({cache:false}) prevention when doing
> replaceWith.
> I have solve the problem by using ".html" instead of ".replaceWith".
>
> Thank you for your help. very appreciate it .
>
> Regards,
> MH
>
>
> On Sat, May 5, 2012 at 2:01 PM, Oscar Mederos <omede...@gmail.com> wrote:
>
>> Hello Min,
>>
>> On Saturday, May 5, 2012, 1:36:24 PM, you wrote:
>>
>> > hi oscar,
>>
>> > it works, but the problem in jquery load didn't refresh the page after
>> I have loaded.
>> > it will always use the outdated html. I have tried to use ajaxsetup
>> cache:false etc.
>> > but seems like once it loaded. if form return validation error, even we
>> have close
>> > and call jquery load again. it will still static and show the last
>> validation error.
>>
>> > how you solve this issue? seems like more to javascript itself .
>>
>> I'm not sure why it isn't modifying the page correctly, because the
>> following line should do it:
>>
>> $("#my-form").replaceWith(data.message);
>>
>> - Are you sure the form isn't being validated in the server-side?
>> - Are you sure the request is being made to the server? (maybe an error
>> occurs on the client-side and the request is never made).
>> - Could you show us the entire code you are using?
>>
>> I suggest you doing two things:
>> 1) Load the page, and before submitting the form, store the source
>> code of the page. Then store it again once you submit it, so that you
>> can compare both source codes.
>> 2) Debug that jQuery code either with Chrome's Developer Tools, or
>> Firebug for Firefox.
>>
>> > Regards,
>> > MH
>>
>>
>> --
>> Oscar Mederos
>> omede...@gmail.com
>>
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