Nik, if I remove the csrf decorator and leave the middleware in place, I
get the 403. Is there a way to add the token on the POST command, or is
there another way of leaving the middleware in place, but turn off csrf
without using the decorator?
On Thursday, July 5, 2012 8:33:51 PM UTC-4, Jeff Silverman wrote:
>
> Nik, I will give that a try. The reason for the decorator was that I was
> getting 403 forbidden, and the decorator made that one go away. If I
> remove the csrf from the settings file, will that solve that problem?
>
>
> On Tuesday, July 3, 2012 9:32:20 AM UTC-4, Jeff Silverman wrote:
>>
>> Below is the code from the views.py
>>
>> The 405 is retunred from the 'return super(DjangoSoapApp,
>> self).__init__(Application(services, tns))' statement. I am using
>> python 2.6, soaplib20 and django 1.3. I am struggling to understand
>> what exactly is wrong here.
>>
>>
>>
>> class HelloWorldService(DefinitionBase):
>> @soap(String,Integer,_returns=Array(String))
>> def say_smello(self,name,times):
>> results = []
>> for i in range(0,times):
>> results.append('Hello, %s'%name)
>> return results
>>
>> class DjangoSoapApp(WSGIApplication):
>> csrf_exempt = True
>>
>> def __init__(self, services, tns):
>> """Create Django view for given SOAP soaplib services and
>> tns"""
>>
>> return super(DjangoSoapApp,
>> self).__init__(Application(services, tns))
>>
>> def __call__(self, request):
>> django_response = HttpResponse()
>>
>> def start_response(status, headers):
>> django_response.status_code = int(status.split(' ', 1)[0])
>> for header, value in headers:
>> django_response[header] = value
>>
>> response = super(DjangoSoapApp, self).__call__(request.META,
>> start_response)
>> django_response.content = '\n'.join(response)
>>
>> return django_response
>>
>> # the view to use in urls.py
>> hello_world_service = DjangoSoapApp([HelloWorldService], '__name__')
>>
>
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