Yep it's a problem with my views.py and my template or html page.
My html page needed the csrf token tag: {% csrf_token %}
and my view needed: return render_to_response('about.html',
context_instance=RequestContext(request))
so thanks for the help!!!
On Wednesday, July 11, 2012 7:58:54 AM UTC-4, Sergey Fursov wrote:
>
> Ok, I tried your code, just added in models.py fake owners model to
> correct foreign key
>
> class Owners(models.Model):
> num = models.IntegerField()
>
> def __unicode__(self):
> return unicode(self.num)
>
> and create views.py with three lines of code:
>
> def page(request):
> form = WebrequestsForm(own_id=1)
> return render_to_response('page.html', {'form': form})
>
> and it works!
> May be problem in your views.py?
>
>
> 2012/7/10 Сергей Фурсов <geyse...@gmail.com>
>
>> as described in error message your view function have to use
>> RequestContext<http://docs.djangoproject.com/en/dev/ref/templates/api/#subclassing-context-requestcontext>
>> for
>> the template, instead of Context.
>> your view should looks like
>>
>> def about(request):
>> if request.method == 'POST':
>> return HttpResponseRedirect('/about/')
>> elif request.method == 'GET':
>> return render_to_response('about.html',
>> context_instance=RequestContext(request))
>> else:
>> raise Http404()
>>
>> note that you redirect (HttpResponseRedirect) to url, but
>> render (render_to_response) template with context
>>
>> also I changed action for form in tempalte to /about/ to handle POST and
>> GET requests in same view
>>
>> hope this helps
>>
>> 2012/7/10 JJ Zolper <codinga...@gmail.com>
>>
>>> Here is the error I received with debug set to true for Django:
>>>
>>> Forbidden (403)
>>>
>>> CSRF verification failed. Request aborted.
>>> Help
>>>
>>> Reason given for failure:
>>>
>>> CSRF token missing or incorrect.
>>>
>>>
>>> In general, this can occur when there is a genuine Cross Site Request
>>> Forgery, or when Django's CSRF
>>> mechanism<http://docs.djangoproject.com/en/dev/ref/contrib/csrf/#ref-contrib-csrf>
>>> has
>>> not been used correctly. For POST forms, you need to ensure:
>>>
>>> - The view function uses
>>> RequestContext<http://docs.djangoproject.com/en/dev/ref/templates/api/#subclassing-context-requestcontext>
>>> for
>>> the template, instead of Context.
>>> - In the template, there is a {% csrf_token %} template tag inside
>>> each POST form that targets an internal URL.
>>> - If you are not using CsrfViewMiddleware, then you must use
>>> csrf_protect on any views that use the csrf_token template tag, as
>>> well as those that accept the POST data.
>>>
>>> You're seeing the help section of this page because you have DEBUG =
>>> True in your Django settings file. Change that to False, and only the
>>> initial error message will be displayed.
>>>
>>> You can customize this page using the CSRF_FAILURE_VIEW setting.
>>>
>>>
>>> I'm wondering if this is caused because I don't have a redirect page for
>>> my 'POST' HTML submit.
>>>
>>> Now my code...
>>>
>>> URLCONF:
>>>
>>> from django.conf.urls.defaults import patterns, include, url
>>>
>>> from MadTrak.manageabout.views import about, about_form
>>>
>>>
>>> # Uncomment the next two lines to enable the admin:
>>>
>>> from django.contrib import admin
>>>
>>> admin.autodiscover()
>>>
>>>
>>> urlpatterns = patterns('',
>>>
>>>
>>> (r'^about_form/', about_form),
>>>
>>> (r'^about/', about),
>>>
>>>
>>> # Examples:
>>>
>>> # url(r'^$', 'MadTrak.views.home', name='home'),
>>>
>>> # url(r'^MadTrak/', include('MadTrak.foo.urls')),
>>>
>>>
>>> ## url(r'^$', 'MadTrak.views.home', name='home'), with a view named home
>>>
>>> ## url(r'^listen/', 'MadTrak.views.home', name='home'), with a view
>>> named home
>>>
>>> ## url(r'^home/', 'MadTrak.views.home', name='home'), with a view named
>>> home
>>>
>>>
>>> # Uncomment the admin/doc line below to enable admin documentation:
>>>
>>> # url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
>>>
>>>
>>> # Uncomment the next line to enable the admin:
>>>
>>> url(r'^admin/', include(admin.site.urls)),
>>>
>>> )
>>>
>>>
>>> views.py in my manageabout app:
>>>
>>> from django.http import HttpResponseRedirect
>>>
>>> from django.shortcuts import render_to_response
>>>
>>> from MadTrak.manageabout.models import AboutMadtrak
>>>
>>>
>>> def about_form(request):
>>>
>>> return render_to_response('about_form.html')
>>>
>>>
>>> def about(request):
>>>
>>> if request.method == 'POST':
>>>
>>> # do_something_for_post()
>>>
>>> return HttpResponseRedirect('about.html')
>>>
>>> elif request.method == 'GET':
>>>
>>> return render_to_response('/')
>>>
>>> else:
>>>
>>> raise Http404()
>>>
>>>
>>> model where i tried to set up my database to recieve the information
>>> posted:
>>>
>>> from django.db import models
>>>
>>>
>>> class AboutMadtrak(models.Model):
>>>
>>> name = models.CharField(max_length=30)
>>>
>>> title = models.CharField(max_length=60)
>>>
>>> bio = models.CharField(max_length=200)
>>>
>>> website = models.URLField()
>>>
>>>
>>> def __unicode__(self):
>>>
>>> return self.nam
>>>
>>>
>>> my template for the about form submission:
>>>
>>>
>>> <html>
>>>
>>> <title>About-Form</title>
>>>
>>> <head>
>>>
>>>
>>> </head>
>>>
>>> <body>
>>>
>>>
>>> MadTrak About Page, Yo!
>>>
>>>
>>> <p></p>
>>>
>>>
>>> <form action="/about_form/" method="post">
>>>
>>> {% csrf_token %}
>>>
>>> <p>Name: <input type="text" name="name" value=""></p>
>>>
>>> <p>Title: <input type="text" name="title" value=""></p>
>>>
>>> <p>Bio: <textarea name="bio" rows="10" cols="50"></textarea></p>
>>>
>>> <p>Website: <input type="text" name="website" value=""></p>
>>>
>>> <input type="submit" value="Submit">
>>>
>>> </form>
>>>
>>>
>>> </body>
>>>
>>> </html>
>>>
>>>
>>>
>>> In conclusion I am fairly new to even 'POST' and 'GET' operations so I
>>> apologize haha. Anyways, I see the CSRF error and I was confused because i
>>> recall that having to do with security? An open operation from submission
>>> to a redirect page? I'm not sure.
>>>
>>> All I wanted to accomplish was to be able to post the data in that
>>> template and see the result in my in my MadTrak database. That's it. Just
>>> see the data as an item in my database. Any help is welcomed as I try to
>>> iron this out!
>>>
>>> Cheers to all the Django developers out there!
>>>
>>> JJ Zolper
>>>
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>>
>>
>
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