On Tuesday, 27 November 2012 15:37:19 UTC, Peter Edström wrote: > Hello, > > I've set up a user profile according to > this<https://docs.djangoproject.com/en/dev/topics/auth/#storing-additional-information-about-users>and > now I'm trying to access the id of the currently logged in user in my > urls.py, like this: > > # urls.py >> from django.contrib.auth.decorators import login_required >> from django.views.generic import list_detail >> from myproj.myapp.models import App1 >> > >> app1_info = { >> 'queryset': App1.objects.filter(employee=????????)), >> 'template_name': 'template.html', >> } >> >> urlpatterns = patterns('', >> (r'^logged_in/$', login_required(list_detail.object_list), app1_info), >> ) >> > > In App1 I have a OneToOneField to my user profile, I want to list > everything in App1 filtered on the currently logged in user (employee = > current_user). > Every example I find in the docs uses the request.user.username, but I > have no request method here. > > Any clues? >
This isn't something you do in the urlconf. You do that in your view, where the current user is available already as `request.user`. -- DR. -- You received this message because you are subscribed to the Google Groups "Django users" group. To view this discussion on the web visit https://groups.google.com/d/msg/django-users/-/s4FNkeMZO8UJ. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
