FYI: OS=Mac OSX 107, Python 2.7.1 Experience : CGI programming 17 years, python 10 years. Django, FastCGI - newbie .htaccess - pretty shaky
I'd like to work with django out of the box as fastcgi. I have a test site set up. With (code) python manage.py runserver 8000 (/code) My test sites is accessible by http://localhost:8000 With .htaccess as follows (code) AcceptPathInfo On Options +SymLinksIfOwnerMatch DirectoryIndex test0_Loader.py AddHandler fcgid-script .py RewriteEngine on RewriteCond $1 !^(test0_Loader\.py|images|css|js|robots\.txt|favicon\.ico) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ ./test0_Loader.py/$1 [L,QSA] (/code) If I point my browser to http://localhost/test0 I get the source code for test0_Loader.py printed to the screen. NOTE: Although the (code) python manage.py runserver (/code) method works fine for development, but for deployment, I will be on shared hosting without any port numbers open but the default. mod_fastcgi is enabled for apache. I could use some direction here. thanks -- Tim tim at tee jay forty nine dot com or akwebsoft dot com http://www.akwebsoft.com -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
