On 2013-02-27, at 18:23 , Stefano Tranquillini wrote: > Django 1.5 is just came out and it ships the StreamingHttpResponse. > > What i want to do is to print the output of a stream response into a > template
I'm pretty sure that doesn't make sense: the template has to be rendered, and I'm pretty sure a given Django template doesn't render to a stream given https://code.djangoproject.com/ticket/13910 is still open. What you *can* do is work the other way around, create a StreamingHttpResponse and fill it with multiple renderings of a template. > , having for example a bar that grows based on the streamed data > (something similar to a loading bar). If your render target is HTML, that doesn't make any sense either. That's just not how HTML works. You might be able to send a CSS stream with incremental rules overwriting one another and growing a "loading bar", but that's abuse of the whole thing and not of much use. > so far i've found a solution that basically is to write the pieces of the > final html page into the generator function, so each yield does a > render_to_text of a piece of the final html page (i splitted it manually) > putting each time the data just processed. > > The problem of this solution is that i can't have the loading bar. What I'm > able to have are incremental data, so i can print out the list of processed > data, but it's different to what i want to do. > > Is there a way to do what i would like to do? Think about it again and explain what you're originally trying to achieve. You seem to be approaching the problem from the wrong direction, as far as I can read. -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/django-users?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
