Thank you for your answer, that i managed to achive,
what I want is to display on the admin object list of object B, display 
name_B and name_A

Anyway
Thanks
Alex


Terça-feira, 7 de Maio de 2013 13:43:59 UTC+1, Sergiy Khohlov escreveu:
>
> this  not hard : 
>
> from django.db import models
>
> # Create your models here.
>
> class A(models.Model):
>      """ model A """
>      name_a   = models.CharField(max_length=20)
>
>      def __unicode__(self):
>          return self.name_a
>
> class B(models.Model):
>      """ Model B"""
>      keyfield = models.ForeignKey('mymodel.A')
>      name_b   = models.CharField(max_length=20)
>      def __unicode__(self):
>          
>          return self.name_b
>
>
>
> serg@debian:~/project/linkmodels/modeltest$ python manage.py  shell 
> Python 2.7.3 (default, Mar  5 2013, 01:19:40) 
> Type "copyright", "credits" or "license" for more information.
>
> IPython 0.13.2 -- An enhanced Interactive Python.
> ?         -> Introduction and overview of IPython's features.
> %quickref -> Quick reference.
> help      -> Python's own help system.
> object?   -> Details about 'object', use 'object??' for extra details.
>
> In [1]: from mymodel.models import A, B
>
> In [2]: A.objects.all()
> Out[2]: []
>
> In [3]: object_A = A('object_A')
>
> In [4]: A.objects.all()
> Out[4]: []
> In [5]: object_A.save()
>
>
> In [6]: object_B = B(name_b = 'object_B')
>
> In [7]: object_B.keyfield = object_A
>
> In [8]: object_B.save()
>
> In [9]: B.objects.all()
> Out[9]: [<B: object_B>]
>
> In [10]: B.objects.filter(id=1)
> Out[10]: [<B: object_B>]
>
> In [11]: B.objects.filter(id=1)[0]
> Out[11]: <B: object_B>
>
> In [12]: B.objects.filter(id=1)[0].name_b
> Out[12]: u'object_B'
>
> In [13]: B.objects.filter(id=1)[0].keyfield
> Out[13]: <A: object_A>
>
> In [14]: B.objects.filter(id=1)[0].keyfield.name_a
> Out[14]: u'object_A'
>
>
>
> Many thanks,
>
> Serge
>
>
> +380 636150445
> skype: skhohlov
>
>
> On Tue, May 7, 2013 at 11:43 AM, alexan...@gmail.com <javascript:> <
> alexan...@gmail.com <javascript:>> wrote:
>
>> Hi
>>
>> class A(models.Model):
>>   f1=...
>>   f2=...
>>   f3=...
>>
>> class B(models.Model)
>>   f4=Foreignkey(A)
>>   f5=...
>>   f6=...
>>
>>
>> class BAdmin(admin.ModelAdmin)
>>   list_display= (f4,f4__f2,f4__f3)     # this does not work
>>
>> How do I in the list display ob objects B, diaplay some fields from A 
>> linked by the foreign key.
>> this syntax works for filter in class BAdmin!
>>
>> Regards
>> Alexandre Rua
>>  
>> -- 
>> You received this message because you are subscribed to the Google Groups 
>> "Django users" group.
>> To unsubscribe from this group and stop receiving emails from it, send an 
>> email to django-users...@googlegroups.com <javascript:>.
>> To post to this group, send email to django...@googlegroups.com<javascript:>
>> .
>> Visit this group at http://groups.google.com/group/django-users?hl=en.
>> For more options, visit https://groups.google.com/groups/opt_out.
>>  
>>  
>>
>
>

-- 
You received this message because you are subscribed to the Google Groups 
"Django users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to django-users+unsubscr...@googlegroups.com.
To post to this group, send email to django-users@googlegroups.com.
Visit this group at http://groups.google.com/group/django-users?hl=en.
For more options, visit https://groups.google.com/groups/opt_out.


Reply via email to