Looks like it has something to do with calling subprocess from the server because this gives the same error:
response = subprocess.check_output(['which', 'ls']) Anyone have any suggestions? On Wednesday, June 19, 2013 4:01:30 PM UTC-7, Chad Vernon wrote: > > I'm trying to use ffmpeg to generate a thumbnail for a video. It works > just fine when I call it from a python shell and when I test it in "python > manage.py shell". However when I try to run from the apache server running > locally, I get an error: > > # normally I call subprocess.call, but for debug here I'm calling > check_call > response = subprocess.check_call(['ffmpeg', '-i', self.file.path], > stderr=fh) > > # actual path taken out for brevity > Command '['ffmpeg', '-i', u'...']' returned non-zero exit status -6 > > I've verified that the video path is correct. > > Any suggestions? > > Thanks! > Chad > -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users. For more options, visit https://groups.google.com/groups/opt_out.
