Hi, I've got 3 models: Artist, Album and Song.
For getting an artist info I use: (r'^artists/(?P<slug>[-\w]+)/$', 'django.views.generic.list_detail.object_detail', dict(info_dict, slug_field='identificador')), I want an url like www.mysite.com/artists/black_eye_peas/albums/album_name for getting all songs of that album that belongs to that artist. how could I do that? problem: it contains 2 slugfields.... thank you! --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~----------~----~----~----~------~----~------~--~---
