What are you trying to do? Typical approach would be to use Javascript to pull
the images. Take a look at dajaxice.
—
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On Mon, Nov 18, 2013 at 1:57 PM, Alex Karargyris <akarargy...@gmail.com>
wrote:
> So thanks to Simon I was able to make this work. Here is the code for those
> who might be interested:
> yield "<html>"
> yield '<meta http-equiv="refresh" content="0.01" />'
> yield "<body>\n"
> rval, frame = settings.CAP.read()
> gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)
> cv2.imwrite('media/image.jpeg', gray, [int(cv2.IMWRITE_JPEG_QUALITY), 90
> ])
> x={"src": "..%s/image.jpeg" % (settings.MEDIA_URL), "alt": "Video Frame"
> }
> yield '<img src="%(src)s" alt="%(alt)s"/>' % x
> yield "</body></html>\n"
> However as it doesn't stream the images but instead it saves and the html
> is refreshed every 0.01 secs. This does not seem to be an elegant solution
> because a) there is latency and b) the browser keeps reloading constantly.
> Some of you suggested websockets. Is there some good example for Django +
> Websockets for streaming images to the browser?
> Thanks a lot!
> -Alex
> On Friday, November 15, 2013 11:15:21 AM UTC-5, Alex Karargyris wrote:
>>
>> I have this simple app that I opens webcam and processes the frames using
>> OpenCV. In my views.py I have the following code:
>>
>> def processImage():
>>
>> while True:
>>
>> rval, frame = settings.CAP.read() //Read frames from webcam
>> gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY) //Make
>> frame grayscale
>> pil_img = Image.fromarray(gray)
>>
>> response = HttpResponse(mimetype="image/png")
>> pil_img.save(response, "PNG")
>>
>> return response
>>
>> Although there is a while loop the function runs only once because it is
>> broken by "return response". How could I change the code to make it run
>> constantly?
>>
>>
>>
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