My point was that annotate might work after the other problems were fixed.
Have you re-tested since?  If your annotate still doesn't work then perhaps
someone with more annotate experience than I will comment.



On Wed, Apr 2, 2014 at 12:04 PM, Justin Holmes <jus...@justinholmes.com>wrote:

> No no, the annotate doesn't work - that's the whole reason for my
> question.  See, the annotate doesn't associate instances with the annotated
> attribute, it associated results.
>
> (BTW, good looking out - I have once again fixed the SO question :-))
>
>
> On Wed, Apr 2, 2014 at 10:17 AM, Bill Freeman <ke1g...@gmail.com> wrote:
>
>> 1.  You now have a foreign key to Herd, but you don't have a model by
>> that name.  It's called LlamaHerd.
>>
>> 2.  I was misinterpreting what you wanted (couldn't get past the lack of
>> a relationship while reading0.  Once the relationship is fixed, your
>> original annotate might work.
>>
>>
>> On Tue, Apr 1, 2014 at 6:20 PM, Justin Holmes <jus...@justinholmes.com>wrote:
>>
>>> You say "use the reverse relation manager in LlamaHerd to build up your
>>> annotation," but that answer the question.
>>>
>>> How can I sort LlamaHerd objects by the DOB of their largest llama?
>>>
>>>
>>> On Tue, Apr 1, 2014 at 6:13 PM, Justin Holmes 
>>> <jus...@justinholmes.com>wrote:
>>>
>>>> Yes, absolutely - my bad.  I have updated to SO question.  I meant the
>>>> models to look like:
>>>>
>>>> class LlamaHerd(models.Model):
>>>>     shepherd = ForeignKey(User)
>>>>
>>>> class Llama(models.Model):
>>>>     size = FloatField()
>>>>     dob =
>>>>  FloatField
>>>>     herd = ForeignKey(Herd, related_name="llamas")
>>>>
>>>>
>>>>
>>>>
>>>> On Tue, Apr 1, 2014 at 6:09 PM, Bill Freeman <ke1g...@gmail.com> wrote:
>>>>
>>>>> Aren't you missing a ForeignKey relationship to tell which LlamaHerd a
>>>>> Llama belongs to?
>>>>>
>>>>> Then you would use the reverse relation manager in LlamaHerd to build
>>>>> up your annotation.
>>>>>
>>>>>
>>>>> On Tue, Apr 1, 2014 at 5:52 PM, Justin Holmes <jus...@justinholmes.com
>>>>> > wrote:
>>>>>
>>>>>> I have come across this problem in several Django projects, but only
>>>>>> just now worked it out in my head enough to make it a cognizable 
>>>>>> question.
>>>>>>
>>>>>> I have also posted it on StackOverflow, here:
>>>>>> http://stackoverflow.com/questions/22797497/using-the-django-orm-to-order-by-a-value-in-a-distinct-related-item
>>>>>>
>>>>>>
>>>>>> Consider this example:
>>>>>>
>>>>>> class LlamaHerd(models.Model):
>>>>>>     shepherd = ForeignKey(User)
>>>>>>
>>>>>> class Llama(models.Model):
>>>>>>     size = FloatField()
>>>>>>     dob = FloatField
>>>>>>
>>>>>> How can I now make a query to get LlamaHerd objects, sorted by the
>>>>>> date of birth of their largest llama?
>>>>>>
>>>>>> It almost feels like I might be able to use annotate:
>>>>>>
>>>>>> LlamaHerd.annotate(largest_llama=Max('llama__size')).order_by('largest_llama__dob')
>>>>>>
>>>>>> ...but the annotate here creates fields with float values, not with
>>>>>> the model instances.
>>>>>>
>>>>>>
>>>>>> --
>>>>>> Justin Holmes
>>>>>> Chief Chocobo Breeder, slashRoot
>>>>>>
>>>>>> slashRoot: Coffee House and Tech Dojo
>>>>>> New Paltz, NY 12561
>>>>>> 845.633.8330
>>>>>>
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>>>>
>>>>
>>>>
>>>> --
>>>> Justin Holmes
>>>> Chief Chocobo Breeder, slashRoot
>>>>
>>>> slashRoot: Coffee House and Tech Dojo
>>>> New Paltz, NY 12561
>>>> 845.633.8330
>>>>
>>>
>>>
>>>
>>> --
>>> Justin Holmes
>>> Chief Chocobo Breeder, slashRoot
>>>
>>> slashRoot: Coffee House and Tech Dojo
>>> New Paltz, NY 12561
>>> 845.633.8330
>>>
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>>
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>
>
>
> --
> Justin Holmes
> Chief Chocobo Breeder, slashRoot
>
> slashRoot: Coffee House and Tech Dojo
> New Paltz, NY 12561
> 845.633.8330
>
> --
> You received this message because you are subscribed to the Google Groups
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>
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