you are calling the function twice, appending every element, and then
appending the whole list!
Le samedi 8 novembre 2014 18:07:04 UTC+1, monoBOT monoBOT a écrit :
>
> Lists are inmutable!!!! You are modifiying the same list everytime you
> invoque that view
> El 07/11/2014 10:08, "termopro" <term...@gmail.com <javascript:>>
> escribió:
>
>> I have a view in Django which calls external library/class. The problem
>> is that for some reason Django keeps caching results coming from previous
>> calls of that class.
>>
>> Please consider the following simple example:
>>
>> Django view:
>>
>> from some_path import Demodef test_view(request):
>> demo = Demo()
>> result = demo.do_something()
>> return render(request, 'test.html',
>> { 'result':result }
>> )
>>
>> Demo class:
>>
>> class Demo():
>> result = []
>>
>> def do_something(self):
>> self.result.append(1)
>> self.result.append(2)
>> self.result.append(3)
>> return self.result
>>
>> You expect result to be [1, 2, 3], right ? WRONG!
>>
>> The first time a page is loaded you'll get the correct result. But on all
>> following requests it will keep incrementing: [1, 2, 3, 1, 2, 3]... [1, 2,
>> 3, 1, 2, 3, 1, 2, 3] ...
>>
>> So my question is obvious - what is going on here ? How do i receive [1,
>> 2, 3] every time i call a class inside Django view ?
>>
>> p.s. - Django 1.7 / MacOSx
>>
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