Hi,
consider two objects,
ls_dic=[{'key1':a , 'key2': b},{'key1':c , 'key2': d}]
num=sum([len(x.values()) for x in ls_dic])
print '%s' % ','.join(sorted(sum([x.values() for x in ls_dic],[])))[:-num]
print '%s' % ','.join(sorted(sum([x.values() for x in ls_dic],[])))[num:]
This is will help a lot.
ls_dic list object is considered for input. I used num object to store
number of values in each directory item of ls_dic list. This object is used
in further 2 print statements. These statements will print in expected
output fashion. Check it out.
Enjoy!!!!!
On Sun, Feb 15, 2015 at 7:59 PM, Shai Efrati <sha...@gmail.com> wrote:
> sorry.
> assuming:
> l = [{'key1':'a' , 'key2': 'b'},{'key1':'c' , 'key2': 'd'}]
>
> for e in l:
> for k, v in e.iteritems():
> print v,
> print
>
> On 2/15/15, Shai Efrati <sha...@gmail.com> wrote:
> > assuming:
> > l = [{'key1':a , 'key2': b},{'key1':c , 'key2': d}]
> >
> > for e in l:
> > for k, v in iteritems(e):
> > print v,
> > print
> >
> >
> >
> > On 2/15/15, aronivi...@gmail.com <aronivi...@gmail.com> wrote:
> >> [{'key1':a , 'key2': b},{'key1':c , 'key2': d}]
> >> a,b
> >> c,d
> >>
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Krishnasagar S. Subhedarpage
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