i find solution for that error
if i change request to :
if 'nums' in request.POST:
nums = request.POST['nums']
else:
nums = False
now i have else error and i think the code in my html form is wrong (inside
the form i copy paste {% csrf_token %}) and again nothing
Forbidden (403)
CSRF verification failed. Request aborted
Help
Reason given for failure:
CSRF token missing or incorrect.
In general, this can occur when there is a genuine Cross Site Request
Forgery, or when Django's CSRF mechanism
<https://docs.djangoproject.com/en/1.8/ref/csrf/> has not been used
correctly. For POST forms, you need to ensure:
- Your browser is accepting cookies.
- The view function passes a request to the template's render
<https://docs.djangoproject.com/en/dev/topics/templates/#django.template.backends.base.Template.render>
method.
- In the template, there is a {% csrf_token %} template tag inside each
POST form that targets an internal URL.
- If you are not using CsrfViewMiddleware, then you must use csrf_protect
on any views that use the csrf_token template tag, as well as those that
accept the POST data.
You're seeing the help section of this page because you have DEBUG = True
in your Django settings file. Change that to False, and only the initial
error message will be displayed.
You can customize this page using the CSRF_FAILURE_VIEW setting.
Τη Τρίτη, 9 Φεβρουαρίου 2016 - 9:47:30 μ.μ. UTC+2, ο χρήστης Xristos
Xristoou έγραψε:
>
> hello,
>
>
> i create some python mathematical function on python idle,
> i want to create website where the user import value numbers on the
> function
> and take the results from that.
> question one,how to connect my mathematical function on the django?
> question two,how to connect input and output from the scipts in the
> website ?
> the second question i ask because input and output from the function is a
> dynamic define from the user
>
>
>
>
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