you are looking something like
https://code.djangoproject.com/ticket/7150
https://code.djangoproject.com/attachment/ticket/7150/admin_view-permission-1.0.patch
https://code.djangoproject.com/attachment/ticket/7150/newforms-admin-view-permission-r7737.patch
https://code.djangoproject.com/ticket/8936
https://code.djangoproject.com/ticket/22452
https://code.djangoproject.com/ticket/18814
https://code.djangoproject.com/ticket/17295
https://code.djangoproject.com/ticket/3984
https://code.djangoproject.com/ticket/2058
https://code.djangoproject.com/ticket/820
I don't know why Django doesn't support readonly view, various proposal was
summit and always was reject.
Django Admin needs Readonly View functionality for a complete
implementation of CRUD.
There is a lot of scenarios where you need readonly view for your staff.
And yes you can implement a readonly in django admin without modify django
core admin with some tricks.
I
2016-10-24 7:26 GMT-06:00 Derek <gamesb...@gmail.com>:
> Would it be possible to add these extra admin methods into a parent class;
> and then have all your individual model admins inherit from it? Ditto for
> the models.py
>
> On Sunday, 8 February 2015 21:15:42 UTC+2, Hangloser Firestarter wrote:
>>
>> Solved.
>>
>> In __init__.py
>> ...
>> from django.db.models.signals import post_syncdb
>> from django.contrib.contenttypes.models import ContentType
>> from django.contrib.auth.models import Permission
>>
>> def add_view_permissions(sender, **kwargs):
>> """
>> This syncdb hooks takes care of adding a view permission too all our
>> content types.
>> """
>> # for each of our content types
>> for content_type in ContentType.objects.all():
>> # build our permission slug
>> codename = "view_%s" % content_type.model
>>
>> # if it doesn't exist..
>> if not Permission.objects.filter(content_type=content_type,
>> codename=codename):
>> # add it
>> Permission.objects.create(content_type=content_type,
>> codename=codename,
>> name="Can view %s" %
>> content_type.name)
>> print("Added view permission for %s" % content_type.name)
>>
>> # check for all our view permissions after a syncdb
>> post_syncdb.connect(add_view_permissions)
>> ...
>>
>> In admin.py
>> ...
>> class MyAdmin(admin.ModelAdmin):
>> def has_change_permission(self, request, obj=None):
>> ct = ContentType.objects.get_for_model(self.model)
>> salida = False
>> if request.user.is_superuser:
>> salida = True
>> else:
>> if request.user.has_perm('%s.view_%s' % (ct.app_label,
>> ct.model)):
>> salida = True
>> else:
>> if request.user.has_perm('%s.change_%s' % (ct.app_label,
>> ct.model)):
>> salida = True
>> else:
>> salida = False
>> return salida
>>
>> def get_readonly_fields(self, request, obj=None):
>> ct = ContentType.objects.get_for_model(self.model)
>> if not request.user.is_superuser and
>> request.user.has_perm('%s.view_%s' % (ct.app_label, ct.model)):
>> return [el.name for el in self.model._meta.fields]
>> return self.readonly_fields
>> ...
>>
>> in models.py
>> ...
>> class City(models.Model):
>> nome_cidade = models.CharField(max_length=100)
>> estado_cidade = models.CharField(max_length=100)
>> pais_cidade = models.CharField(max_length=100)
>>
>> def __str__(self):
>> return self.nome_cidade
>>
>> class Meta:
>> permissions = (
>> ('view_city', 'Can view city'),
>> )
>> ...
>>
>> Thank's for help!
>>
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