See:
https://stackoverflow.com/questions/8953119/python-waiting-for-external-launched-process-finish
François
> On Aug 7, 2017, at 2:35 PM, Ronaldo Bahia <[email protected]> wrote:
>
> How can I do that?
>
> Ronaldo Bahia
> +55 11 3280 6971
> +55 11 963 622 581
>
> Materiais gratuitos para o RH:
> - ROI - Melhorando Indicadores no RH
> - Manual do Recrutador Moderno
>
> 2017-08-07 18:32 GMT-03:00 "Александр Христюхин (roboslone)"
> <[email protected]>:
> You can wait for subprocess to finish and not rely on time.sleep.
>
>> On 7 Aug 2017, at 23:57, Ronaldo Bahia <[email protected]> wrote:
>>
>> Turns out unoconv takes 2 seconds to perform the file conversion.
>> So after the file conversion, I had to set time.sleep(3) before upload a
>> file to S3.
>>
>> And after 1 week I got this working using variables.
>>
>> Thanks
>>
>> Ronaldo Bahia
>> +55 11 3280 6971
>> +55 11 963 622 581
>>
>> Materiais gratuitos para o RH:
>> - ROI - Melhorando Indicadores no RH
>> - Manual do Recrutador Moderno
>>
>> 2017-08-07 17:17 GMT-03:00 Ronaldo Bahia <[email protected]>:
>> I don't know why but if I set the string ("cv.pdf"), it process just fine.
>> If I use a variable instead, it doesn't.
>>
>> Here is the working code:
>>
>> # convert to PDF
>> env = os.environ.copy()
>> env['HOME'] = '/tmp'
>> subprocess.Popen(["unoconv","-f", "pdf", "-o", "cv.pdf","%s" %
>> (file_in)], env = env)
>>
>> # Define S3 path
>> resume_path = 'resumes/%s/' % str(date.today())
>>
>> # key is the S3 file name
>> key = '%s%s' % (resume_path, file_out)
>>
>> # delete local file
>> subprocess.call("rm -f %s" % user_cv_file, shell=True)
>>
>> # update the new file format
>> user_cv.resume = key
>> user_cv.save()
>>
>> # S3 Connection
>> conn = S3Connection(settings.AWS_ACCESS_KEY_ID,
>> settings.AWS_SECRET_ACCESS_KEY)
>> bucket_out = Bucket(conn, settings.AWS_STORAGE_BUCKET_NAME)
>> k_out = Key(bucket=bucket_out, name=user_cv.resume)
>>
>> # Upload to S3
>> k_out.set_contents_from_filename('cv.pdf')
>> k_out.make_public()
>>
>> # deleta o arquivo localmente
>> subprocess.call("rm -f cv.pdf", shell=True)
>>
>> Ronaldo Bahia
>> +55 11 3280 6971
>> +55 11 963 622 581
>>
>> Materiais gratuitos para o RH:
>> - ROI - Melhorando Indicadores no RH
>> - Manual do Recrutador Moderno
>>
>> 2017-08-07 8:16 GMT-03:00 "Александр Христюхин (roboslone)"
>> <[email protected]>:
>> Well, yeah, you're using local path basically. And you should NEVER use
>> .split('/')[-1] to determine file basename, take a look at os.path module
>> instead.
>>
>> But that's not the point. You should try to use absolute path, I believe it
>> would do the trick.
>>
>>> On 4 Aug 2017, at 17:49, Ronaldo Bahia <[email protected]> wrote:
>>>
>>> the method is called in a def post() within a class view:
>>>
>>> user_cv = CandidateCV.objects.get(user=request.user)
>>> user_cv_file = str(user_cv.resume).split('/')[-1]
>>> s3upload(user_cv_file)
>>>
>>> The file is converted from doc to pdf in server project folder, where
>>> manage.py is.
>>> So probably there is no absolute path.
>>>
>>> How can I solve it?
>>>
>>> Thanks
>>> Ronaldo Bahia
>>> +55 11 3280 6971
>>> +55 11 963 622 581
>>>
>>> Materiais gratuitos para o RH:
>>> - ROI - Melhorando Indicadores no RH
>>> - Manual do Recrutador Moderno
>>>
>>> 2017-08-03 1:36 GMT-03:00 "Александр Христюхин (roboslone)"
>>> <[email protected]>:
>>> Hi,
>>>
>>> Are you sure s3file contains absolute path? I can't see where s3upload is
>>> being called.
>>>
>>> Also, you might wanna use os.remove instead of calling subprocess.
>>> You also might wanna check out PEP-8 and Sphinx for your docstrings.
>>>
>>>> On 2 Aug 2017, at 02:28, Ronaldo Bahia <[email protected]> wrote:
>>>>
>>>> Hi everyone, can you help me?
>>>> Thanks in advance
>>>>
>>>> Thread:
>>>> https://stackoverflow.com/questions/45449102/django-python-oserror-no-such-file-or-directory-but-file-exists
>>>>
>>>> Code:
>>>>
>>>>
>>>>
>>>> down vote
>>>> favorite
>>>> I'm converting doc and docx files to pdf in the server using unoconv with
>>>> LibreOffice. And I need to upload to S3 the converted file.
>>>>
>>>> I can convert with success the files and I can see them in the server.
>>>>
>>>> But when I try to upload the pdf, I get the error. What am I missing?
>>>>
>>>> Thanks in advance
>>>>
>>>> This works just fine:
>>>>
>>>> import
>>>> subprocess
>>>>
>>>> from boto.s3.connection import S3Connection, Bucket, Key
>>>>
>>>>
>>>>
>>>> def doc_to_pdf(user):
>>>>
>>>>
>>>> '''
>>>> Convert doc or docx to PDF.
>>>>
>>>> parameter user: is a request.user
>>>>
>>>> Usage:
>>>> doc_to_pdf(self.request.user):
>>>> '''
>>>>
>>>>
>>>> user_cv
>>>> = CandidateCV.objects.get(user=user)
>>>>
>>>> user_cv_file
>>>> = str(user_cv.resume).split('/')[-1] # tem que ser PDF
>>>>
>>>> user_cv_filetype
>>>> = user_cv_file.split('.')[-1]
>>>>
>>>>
>>>>
>>>> if not user_cv_filetype in settings.PDF_FILE_TYPE:
>>>>
>>>>
>>>> # Se não for PDF
>>>>
>>>> file_in
>>>> = user_cv.resume.
>>>> url
>>>> file_name
>>>> = file_in.split('/')[-1]
>>>>
>>>>
>>>> # download
>>>>
>>>> urllib
>>>> .request.urlretrieve(file_in, file_name)
>>>>
>>>> file_out
>>>> = user_cv_file.split('.')[0] + '.pdf'
>>>>
>>>>
>>>>
>>>> # converte para PDF
>>>>
>>>> env
>>>> = os.environ.copy()
>>>>
>>>> env
>>>> ['HOME'] = '/tmp'
>>>>
>>>> subprocess
>>>> .Popen(["unoconv","-f", "pdf", "%s" % (file_in)], env = env)
>>>>
>>>>
>>>>
>>>> # Define a path para salvar o documento na S3
>>>>
>>>> resume_path
>>>> = 'resumes/%s/' % str(date.today())
>>>>
>>>>
>>>>
>>>> # key é o nome do arquivo na S3
>>>>
>>>> key
>>>> = '%s%s' % (resume_path, file_out)
>>>>
>>>>
>>>>
>>>> # deleta o arquivo localmente
>>>>
>>>> subprocess
>>>> .call("rm -f %s" % user_cv_file, shell=True)
>>>>
>>>>
>>>>
>>>> # Salva o novo formato no banco
>>>>
>>>> user_cv
>>>> .resume =
>>>> key
>>>> user_cv
>>>> .save()
>>>> This is the code in which I get the error in line:
>>>> k_out.set_contents_from_filename(s3file)
>>>>
>>>> def s3upload(s3file):
>>>>
>>>>
>>>>
>>>> # Conecta na AWS S3
>>>>
>>>> conn
>>>> = S3Connection(settings.AWS_ACCESS_KEY_ID, settings.AWS_SECRET_ACCESS_KEY)
>>>>
>>>> bucket_out
>>>> = Bucket(conn, settings.AWS_STORAGE_BUCKET_NAME)
>>>>
>>>> k_out
>>>> = Key(bucket=bucket_out, name=s3file)
>>>>
>>>>
>>>>
>>>> # Define a path para salvar o documento na S3
>>>>
>>>> resume_path
>>>> = 'resumes/%s/' % str(date.today())
>>>>
>>>>
>>>>
>>>> # key é o nome do arquivo na S3
>>>>
>>>> key
>>>> = '%s%s' % (resume_path, s3file)
>>>>
>>>> k_out
>>>> .key =
>>>> key
>>>>
>>>>
>>>> # Salva na AWS S3
>>>>
>>>> k_out
>>>> .set_contents_from_filename(s3file)
>>>>
>>>> k_out
>>>> .make_public()
>>>>
>>>>
>>>>
>>>> # deleta o arquivo localmente
>>>>
>>>> subprocess
>>>> .call("rm -f %s" % s3file, shell=True)
>>>>
>>>>
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