Hi again,
and as I said, Django templating language is not a programming language and
it doesn't support it (it's by design).
If your graphobject is a list of items, use iterating it over as Matthew
Pava suggested in his reply.
Otherwise you need to either create custom tag/filter that returns what you
want, or change dataformat suitable for displaying and processing in
template.
On Thu, Apr 19, 2018 at 7:35 PM, <shawn...@gmail.com> wrote:
> As I said, the data is already stored in variable: graphobject, I can
> simply achieve my goal by coding like this: {{% graphobject.1%}}, {{%
> graphobject.2 %}} ...... But I want a loop to do that
>
> 在 2018年4月19日星期四 UTC+2下午6:29:18，Jani Tiainen写道：
>>
>> Hi. Django templating language isn't programming language. It can't do
>> that. You need to prepare data suitable for displaying in your view.
>>
>>
>> On Thu, Apr 19, 2018 at 7:01 PM, <shaw...@gmail.com> wrote:
>>
>>> I am currently working on django.
>>>
>>> I have a list of values which stored in 'graphobject', and 'metarange'
>>> is defined as range(0,59). In that case, how could I use numbers as
>>> argument to display the value stored in graphobject? I tried using
>>> following codes but it doesn't work
>>>
>>>
>>> {% for i in metarange %}{% if graphobject.i != '' %}{{ graphobject.i }}{%
>>> endif %}{% endfor %}
>>>
>>>
>>> Please tell me how could I do this?
>>>
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>>
>>
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>> Jani Tiainen
>>
>> - Well planned is half done, and a half done has been sufficient before...
>>
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