UPDATE: Finally figured it out! I ultimately did this by overriding 
`perform_create()` in my [Django Rest Framework 
view](https://www.django-rest-framework.org/api-guide/generic-views/) and 
making my changes after saving the object.

On Sunday, February 10, 2019 at 8:34:44 AM UTC-5, Nick Emery wrote:
>
> I am trying to wrap up my first app using Django (specifically Django 
> Rest Framework which may change the save behavior), but have run into an 
> issue that I haven't been able to solve for about 10 hours now.
>
> I am trying to override the save() method of a model to modify a field on 
> a bunch of child objects when it is created; however, I can't figure out 
> *any* way get the objects or ids for the children.
>
> My code looks something like:
> class Parent(models.Model):
>    """When I create this, I want the children to be modified."""
>    def save(self, *args, **kwargs):
>        if not self.pk:
>            self._begin(*args, **kwargs)
>        else:
>            super(Parent, self).save(*args, **kwargs)
>
>     def _begin(self, *args, **kwargs):
>        super(Parent, self).save(*args, **kwargs)
>        print(self.child_set.all())  # --> This gives: "<QuerySet []>"
>        for i in self.child_set.all():
>            i.last_name = self.last_name
>            i.save()
>
>     last_name = models.CharField(max_length=100)
>
>
> class Child:
>    parent = models.ForeignKey(
>        'Parent',
>        on_delete=models.SET_NULL,
>        null=True,
>     )
>    last_name = models.CharField(max_length=100)
>
> ANY way to modify the children when the parent is saved would be a life 
> saver (even if hacky or sub-optimal).
>

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