Thanks for the help, this is showing only one value in dictionary at a time
. There is no fault here but i have a question can we run multiple search
query in same page with different id ? And it shows that error even now
On Wed, Apr 3, 2019 at 5:56 PM dvij parekh <dvijparekh1...@gmail.com> wrote:
>
> seems like search1 key is containg multi value dictionary and you are
> checking it with == which is for single value
> after
> *search1 = request.POST['search1'] *
> put
> *print(* *search1* *)*
> *return "hello"*
>
> and comment code remaining below ,check terminal it will show you how
> many value you have in dictionary
>
>
> On Wed, Apr 3, 2019 at 5:03 PM Abhineet Baranwal <
> suabhineetbaran...@gmail.com> wrote:
>
>>
>> *this is my views file which creates an error like
>> django.utils.datastructures.MultiValueDictKeyError: 'search1' . Can anyone
>> tell me where i go wrong?*
>>
>> *def viewstr(request):*
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>>
>> * views = create_store.objects.all() brn =
>> Prod_Brand.objects.all() mi = '' if request.method == 'POST':
>> # mi = '' search1 = request.POST['search1'] if search1 == ''
>> : pass else: mi =
>> create_store.objects.filter(Q(select_brand__Brand__icontains=search1))
>> if mi: return
>> render(request,'viewstr.html',{'vi':mi,'brn':brn}) search =
>> request.POST['search'] if search == '' : pass else
>> : mi =
>> create_store.objects.filter(Q(id__icontains=search)) if
>> mi: return
>> render(request,'viewstr.html',{'vi':mi,'brn':brn}) return
>> render(request,'viewstr.html',{'viewstr':viewstr,'vi':mi,'brn':brn})*
>>
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