Hello everyone
So The possible Solution
Could be
for python:
arr = <Be your array>
for i in arr:
if i % 10 == 3:
print(i)
for java
int[] arr = new int[10]; // Suppose you have 10 element in your array if
you want dynamic array use ArrayList
for(int i : arr){
if(i % 10 == 3){
System.out.println(i);
This Solution will Only work for the positive element.
Thank You
On Thu, Feb 25, 2021 at 9:44 PM Kasper Laudrup <laud...@stacktrace.dk>
wrote:
> On 25/02/2021 16.59, Nagaraju Singothu wrote:
> > Write a program to find the number ends with digit 3 in a array,
> >
> > For example for a array input [6,83,12,54,71,44,293,43,66,13,72,42,163],
> > the output should be 83, 293, 43, 13, 163 - all numbers ends with digit
> 3.
> >
>
> It's probably just my lack of imagination, but I have a very hard time
> seeing how such an algorithm could end up as a calendar widget, but
> please do enlighten us.
>
> Kind regards,
>
> Kasper Laudrup
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to django-users+unsubscr...@googlegroups.com.
> To view this discussion on the web visit
> https://groups.google.com/d/msgid/django-users/04e4e878-7bdf-9aba-31a9-21aa8627f1c1%40stacktrace.dk
> .
>
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to django-users+unsubscr...@googlegroups.com.
To view this discussion on the web visit
https://groups.google.com/d/msgid/django-users/CAL8_rkHaZhFvCF_ByJUEFEcgp-6EiLANRDSP0dcR_TjLUGDyBg%40mail.gmail.com.
