[EMAIL PROTECTED] wrote:
> It looks like it's because (as you said), I'm returning a string, in
> the exception... so how do I do that?
>
> def add_song(request):
> try:
> f = open('/path/to/songs/'+
> request.FILES['song_file']['filename'], 'wb') # wb = write binary
> f.write(request.FILES['song_file']['content'])
> f.close()
> except:
> return HttpResponse("Are you sure you selected a song to
> upload?", mimetype="text/html")
> song = Song(artist_id=request.user.id, song_file=
> "songs/"+request.FILES['song_file']['filename'],song_title=
> request.POST['song_title'],pub_date=datetime.now(),
> description=request.POST['description'])
> song.save()
You're correctly returning an HttpResponse object when an exception is
raised; the problem is that you're not returning anything at the end of
your function, following the `song.save()`. You should append a line
like:
return HttpResponseRedirect(some_url)
"some_url" should be the URL for an "upload successful" page.
-Zak
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