all_action=ActionGame.objects.all()
my_action = []
for action in all_action:
my_action.append(action)
last_action = my_action[-1]
On Tue, Feb 28, 2023 at 1:05 PM Andréas Kühne <andreas.ku...@hypercode.se>
wrote:
> Se comments below.
>
>
> Den fre 24 feb. 2023 kl 12:14 skrev Byansi Samuel <
> samuelbyans...@gmail.com>:
>
>> Hey everyone, l got a problem. Am trying to retrieve a single latest
>> object added everytime, and display it in the template.
>> Below is my codes but;
>>
>> Help me figure it out the source of the problem in these different
>> instances below 👇
>>
>> _______________________ issue number 1_______
>>
>> #Action/models.py
>> class ActionGame(models.Model):
>> name=models.Charfield()
>> published=models.DateTimeField()
>>
>> #Action/views.py
>> from Action.models import ActionGame
>>
>> def action (request):
>> latest_action=ActionGame.objects.filter(published=published).
>> latest()
>> Context={ 'latest_action': latest_action }
>> return....
>>
>> But it returns *error* :
>> name 'published' is not defined
>>
>
> You haven't defined what the value of published is. If you want to get the
> last created one the query should be:
> latest_action=ActionGame.objects.latest("published") - that would give you
> the last published item. Another way would be:
> latest_action=ActionGame.objects.order_by("published").last()
>
>
>> ____________________ issue number 2________
>>
>> #Action/models.py
>> class ActionGame(models.Model):
>> name=models.Charfield()
>> published=models.DateTimeField()
>> class Meta:
>> get_latest_by='published'
>>
>> #Action/views.py
>> ........
>> latest_action=ActionGame.objects. latest()
>> .......
>>
>> #but it returns *error* :
>> 'ActionGame' object is not iterable
>>
>> Even if I try this:
>> ............
>> latest_action=ActionGame.objects. latest('published')
>> .......
>>
>> #it returns the Same error:
>> 'ActionGame' object is not iterable
>>
>> But this second issue, the error is referred in #action.html
>>
>> {% for x in latest _action %}
>> <p>{{ x.game_name }}</p>
>> {% endfor %}
>>
>>
> So the latest_action variable that you have sent to the template is an
> instance of ActionGame - and not a list or anything. You can only access
> variables in the ActionGame class. For example:
>
> <p>{{ lastest_action.name }}</p>
>
> would print out the value of the name of the ActionGame instance.
>
> Please l need your assistance.
>>
>> I'm Samuel,
>> Thanks
>>
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>>
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