But is is simple to convert what you have into what you want:
l =
User.objects.filter(username__in=['foo','bar']).values('username', 'email')
emails = dict([(d['username'], d['email']) for d in l])
It would be a little simpler like this:
emails = dict([(r.username, r.email) for r in
User.objects.filter(username__in=['foo','bar'])])
The dict() built-in accepts a number of forms of arguments. One is a
list of pairs, each of which becomes a key and value in the resulting
dictionary.
--Ned.
Malcolm Tredinnick wrote:
> Hi Dirk,
>
> On Sat, 2007-02-10 at 12:02 +0100, Dirk Eschler wrote:
>
>> Hello,
>>
>> i'm trying to get a dict of emails with usernames as keys.
>>
>> User.objects.filter(username__in=['foo', 'bar']).values('username', 'email')
>>
>> The above returns a list of dicts:
>> [{'username': 'foo', 'email': '[EMAIL PROTECTED]'},
>> {'username': 'bar', 'email': '[EMAIL PROTECTED]'}]
>>
>> Is it possible to get a dict like this with Django's db api?:
>> {'foo':'[EMAIL PROTECTED]', 'bar':'[EMAIL PROTECTED]'}
>>
>
> No, it is not possible to get that sort of dictionary back directly from
> Django.
>
> Regards,
> Malcolm
>
>
>
> >
>
>
>
>
--
Ned Batchelder, http://nedbatchelder.com
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