Here's a few ideas:
Solution 1 - use the __main__ module
The downside to this is that it always reads x from the "top-level"
module, in other words, the script that is being run. So when you run
a1, you'll get "a1" when you run a2 module b will then find "a2".
a1.py
------------------
import b
x = "a1"
b.test()
------------------
a2.py
------------------
import b
x = "a2"
b.test()
------------------
b.py
------------------
import __main__
def test():
print __main__.x
------------------
I'm not sure why you're trying to do this, but it looks like having b
reference variable x which is implied to have been defined elsewhere
could cause trouble for you later. x is sort of like a parameter to
make b work differently, so you should probably explicitly pass it to
functions in b or use x to initialize an object of a class from b.
Idea 2 - use a class to encapsulate x
If you wrap up all the functionality you need in a class inside b, you
could then pass x to the constructor and all the subsequent method
calls would have access to x.
a1.py
------------------
import b
x = "a1"
my_b = b.B(x)
my_b.test()
------------------
a2.py
------------------
import b
x = "a2"
my_b = b.B(x)
my_b.test()
------------------
b.py
------------------
class B(object):
def __init__(self, x):
self.x = x
def test(self):
print self.x
------------------
Solution 3 - Use the borg pattern
If you need all modules everywhere to see b with the same value of x,
you could use the borg pattern (singleton would work too, but I like
borg better). This way the first a module that gets imported or run
will set b's value of x forever.
a1.py
------------------
import b
x = "a1"
my_b = b.B(x)
my_b.test()
------------------
a2.py
------------------
import b
x = "a2"
my_b = b.B(x)
my_b.test()
------------------
a3.py - note that this one will print "a1" twice, since module a1
initializes b before a3 can.
------------------
import a1
import b
x = "a3"
my_b = b.B(x)
my_b.test()
------------------
b.py
------------------
class B(object):
borg = None
def __init__(self, x):
if B.borg is None:
B.borg = {}
B.borg['x'] = x
self.__dict__ = B.borg
def test(self):
print self.x
------------------
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