Lucky B skrev:
> how about surrounding the statement with a try and work the leap year
> to regular year case with the exception?
That seems like overkill. There isn't really any leap-year handling
necessary:
import datetime.date as date
def age (d1, d2=None):
if not d2:
d2 = date.today()
years = d2.year - d1.year
if (d2.month,d2.day) < (d1.month,d1.day):
years -= 1
return years
Nis
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