> About the only way to do that is just grab (.*) from the url, and > parse it in your view, looking up slugs as needed
Collin's suggestion may sound daunting, but it's really quite easy: your urls.py can have something like r"^(?P<path>(?:[-\w]+/)*[-\w]+)/?$" and then in your view: def my_view(request, path): # iterate from grandparent -> parent -> child -> grandchild for piece in path.split('/'): do_something(piece) Not too scary and rather easy to understand (except perhaps for the regexp, but that's another matter). -tim --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---