Your objects aren't ids, so you must get ids explicitly.
On 16 дек, 16:34, Michal Ludvig <[EMAIL PROTECTED]> wrote:
> Tim Chase wrote:
> >> How can I retrieve all objects that are *not* in that list?
>
> >> Something like "Model.objects.filter(id__not_in = processed_ids)".
> >> Unlike filter(id__in=...) which works just fine the __not_in modifier
> >> apparently isn't understood by django.
>
> > As commented recently on the list, you want "filter()"'s evil
> > twin "exclude()":
>
> > exclude(id_in=...)
>
> That's it. Thanks.
>
> Now with the above example if I don't have a list of IDs but a list of
> the processed objects I'm not able to pass these as an argument to the
> __in operator.
>
> This: Model.objects.filter(...).exclude(id__in = processed)
> gives me: Truncated incorrect DOUBLE value: 'Model object'
>
> I have to use id__in=[p.id for p in processed] instead.
>
> Am I doing something wrong again or is it expected behaviour?
>
> Thanks
>
> Michal
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