You are doing something like my_instance.author = request.user.id whereas you should do: my_instance.author = request.user. Why? You are working with the Django ORM and it doesn't expect you to give it an User-Id (although it get's saved as that in the db), but an instance of django.contrib.auth.models.User, which maps to the django users table. request.user would be such an instance :)
On Jan 6, 10:08 pm, Darthmahon <[EMAIL PROTECTED]> wrote: > Thanks, should have guessed that! > > For some reason though it is returning the value as 11L. I just want > it to return 11, as it is throwing up an error when trying to use it > like that: > > Invalid value: 'user' should be a <class > 'django.contrib.auth.models.User'> instance, not a <type 'long'> > > I'm using a MySQL database, any way of stripping the L off the end? > > On Jan 6, 9:00 pm, Alex Koshelev <[EMAIL PROTECTED]> wrote: > > > User id - request.user.id > > > On 6 янв, 23:43, Darthmahon <[EMAIL PROTECTED]> wrote: > > > > Hi Guys, > > > > Been looking to get the current id of the user logged in everywhere > > > but can't seem to find how to do this. > > > > Basically in my views.py file I want to insert an entry into a table. > > > Part of this insert requires the current logged in users id. The only > > > bit of information I seem to be able to retrieve is the username like > > > so: > > > > request.user.username > > > > Is there a way of getting the current id of the logged in user? > > > > Thanks, > > > Chris --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
