- If you want retrieve all Person objects that can be viewed by a user, this is possible with this query:
persons = Person.objects.filter( Q(owner=my_user) | Q(public=True) ) my_user is the current logged user, so this query, in designed to be executed in a view function. - If you want to retrieve the current logged user at model level, this is a little more complicated, because models are note designed to see what happen at process level, but it still possible, look at this: http://lukeplant.me.uk/blog.php?id=1107301634 So you can finally write a custom manager in which you will have something like this: my_user = get_current_user() Person.objects.filter( Q(owner= my_user ) | Q(public=True) ) On 17 jan, 03:18, John M <[EMAIL PROTECTED]> wrote: > I want to create a model system where a user can own a record (i.e. > foreign key to users table) and those records are only seen by that > user OR the user can choose to make the record public (boolean field > in model) that allows others to view-only the record. > > I was trying to come up with some simple model managers to do this, > but wanted to get some input first. > > a Model something like: > > class Person(models.Model): > first_name = models.CharField(max_length=30) > last_name = models.CharField(max_length=30) > owner = models.ForeignKey(user) > public = models.booleanfield() > > Basically, this will be a site where users can keep track of their > stuff, but allow others to view what they have too (the person model > isn't what I'm going to use, just an example). > > Any thoughts? > > Thanks --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
