Hi,
Apparently you want an empty list if query has a value, and a list with one
element otherwise (so the "if query" works).
query_string = request.POST.get('q', '')
if query_string:
query = [ query_string ]
else:
query = []
Reading the Python tutorial probably wouldn't hurt.
Remco
On Jan 29, 2008 2:19 PM, MariusB <[EMAIL PROTECTED]> wrote:
>
> In the view take an URL from the query:
> query = request.POST.get('q', '')
>
> and in the template I want to print it out in a list
> {% if query %}
> <ul>
> {% for url in query %}
> <li>{{ url }}</l1>
> {% endfor %}
> </ul>
> {% else %}
> <p>No urls found</p>
> {% endif %}
>
> How do I turn query from a string into a list with one element
> (['<query_value>']) in the view?
> >
>
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---
