Hello,
there is the documentation for creating objects
http://www.djangoproject.com/documentation/db-api/#creating-objects
So I create my test-class and create an object
---------------------------------------------------
class test(models.Model):
first_name = models.CharField(max_length=30)
last_name = models.CharField(max_length=30)
email = models.EmailField()
>>>> a = test(first_name = 'a', last_name = 'b', email = '[EMAIL PROTECTED]')
>>>> a.save()
---------------------------------------------------
This works fine. But I tried to pass a dictionary as paramter
>>>> arr = {'first_name':'c', 'last_name':'d', 'email':'[EMAIL PROTECTED]'}
>>>> a = test(arr)
>>>> a.save()
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/usr/lib/python2.5/site-packages/django/db/models/base.py", line
269, in save
self.save_base()
File "/usr/lib/python2.5/site-packages/django/db/models/base.py", line
305, in save_base
if manager.filter(pk=pk_val).extra(select={'a':
1}).values('a').order_by():
File "/usr/lib/python2.5/site-packages/django/db/models/query.py",
line 84, in __nonzero__
iter(self).next()
File "/usr/lib/python2.5/site-packages/django/db/models/query.py",
line 78, in _result_iter
self._fill_cache()
File "/usr/lib/python2.5/site-packages/django/db/models/query.py",
line 490, in _fill_cache
self._result_cache.append(self._iter.next())
File "/usr/lib/python2.5/site-packages/django/db/models/query.py",
line 514, in iterator
for row in self.query.results_iter():
File "/usr/lib/python2.5/site-packages/django/db/models/sql/query.py",
line 200, in results_iter
for rows in self.execute_sql(MULTI):
File "/usr/lib/python2.5/site-packages/django/db/models/sql/query.py",
line 1466, in execute_sql
cursor.execute(sql, params)
File "/usr/lib/python2.5/site-packages/django/db/backends/util.py",
line 18, in execute
return self.cursor.execute(sql, params)
ProgrammingError: can't adapt
Is this not possible? What's my fault here?
Bernd
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