I understand. Global context = {} was bad solution...
views,py:
context = {
'hot_news': News.objects.filter(hot=True).order_by('-created')[0],
'last_radio_message': VisualRadio.objects.all().order_by('-
created')[0],
'last_totals': Totals.objects.all().order_by('-created')[0],
'last_poll': Poll.objects.all().order_by('-created')[0],
}
def index(request):
context["hot_news"] = News.objects.filter(hot=True).order_by('-
created')[0]
context["news_list"] = News.objects.filter(hot=False).order_by('-
created')[:5]
return render_to_response('index.html', context)
Please, help me to write good code. I don't want repeat code in every
view...
On Jul 2, 3:42 pm, "James Bennett" <[EMAIL PROTECTED]> wrote:
> On Wed, Jul 2, 2008 at 7:09 AM, Alex Koshelev <[EMAIL PROTECTED]> wrote:
> > Client-side caching. Use the `never_cache` decorator
>
> No, that's not it at all.
>
> > On Jul 2, 3:43 pm, Mario <[EMAIL PROTECTED]> wrote:
> >> I look at sql log - django didn't query that, but always query lists,
> >> for example:
> >> context["news_list"] = News.objects.filter(hot=False).order_by('-
> >> created')[:5]
>
> >> what is this? mod_python? caching?
>
> When launched, mod_python loads your code once and only once for each
> server process, and holds it in memory afterward. This is a trade-off
> made or efficiency, because reloading the code on every request would
> significantly slow the server. As a result, whenever you make a change
> to code that runs under mod_python, you must also restart the web
> server.
>
> In addition, any variable assigned at the module global level will
> only be evaluated once, which means that any top-level variable
> declaration which does a database query will only evaluate once per
> server process, rather than appearing to refresh on each request.
>
> --
> "Bureaucrat Conrad, you are technically correct -- the best kind of correct."
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