Wiadomość napisana w dniu 2008-09-02, o godz. 16:23, przez mwebs: > > Hello, > > I want to perform a lookup an getting the object with the highest > integer value. > The Model looks something like this: > > MyModel: > name = .... > number = models.PositiveIntegerField() > > class Meta: > ordering = [-number] > > > So I figured out this: > > highest = MyModel.objects.all()[0] > > Is there another, more elegant way like: highest = > MyModel.object.filter(max(number)), so that I dont have to add the > ordering-attribute in the medta-class?
Sure, you can always specify ordering using order_by(). Ordering defines default ordering, where no ordering is specified. -- We read Knuth so you don't have to. - Tim Peters Jarek Zgoda, R&D, Redefine [EMAIL PROTECTED] --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
