On Fri, Sep 12, 2008 at 2:36 AM, Lance F. Squire <[EMAIL PROTECTED]> wrote: > > Currently using Django version 0.96.3, on a Fedora 8 system. > > I've currently set-up models for 'Manufacturer' and 'System'. System > has a Foreignkey to Manufacturer. > > I'd like to display a list like so: > > Manu A > System a > System b > System c > > Manu B > System a > System b > System c > > Etc... > > Only listing Manufacturers that had systems of type X. > > I was thinking of using code like this in the View, > > man=Manufacturer.objects.all() >>>> for m in man: > ... sys=System.objects.filter(manufacturer=m.id) > ... print m.name > ... for s in sys: > ... print " %s" % s.name > ... > > This works from the shell, but I'm unsure how to get the output to the > template And, I suspect is a terribly inefficient way to do it anyway.
Sounds like you're looking for something like the following: {% for m in man %} {{ m.name }} {% for s in m.sys_set.all %} {{ s.name }} {% endfor %} {% endfor %} (plus some formatting bits, but they should be pretty obvious). This assumes that "man" is in your context, and contains a list of manufacturers (Manufacturer.objects.all(), for instance). The only piece of this puzzle that might be a little confusing is 'm.sys_set.all'. m.sys_set is Django's way of saying "get all the sys objects that are related to the Manufacturer m". More details here: http://docs.djangoproject.com/en/dev/topics/db/queries/#following-relationships-backward Yours, Russ Magee %-) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---