On Thu, Nov 20, 2008 at 6:00 PM, bfrederi <[EMAIL PROTECTED]> wrote:
>
> I am trying to cache a small thumbnail image. The code is a bit
> extensive, but the part this is breaking is that I am opening the
> image file, then this:
>
> cache.set('thumbnail_file', image_file.read())
>
> when I go to retrieve the image with:
>
> cache.get('thumbnail_file')
>
> I get this traceback:
>
> Traceback (most recent call last):
> File "/home/django-code/aubrey_ark/tests.py", line 48, in
> testResourceObject
> ro = ResourceObject(self.meta_id)
> File "/home/django-code/aubrey_ark/resource_handler.py", line 102,
> in __init__
> cache.get(self.meta_id+'_thumbnail')
> File "/usr/lib/python2.5/site-packages/django/core/cache/backends/
> memcached.py", line 30, in get
> return smart_unicode(val)
> File "/usr/lib/python2.5/site-packages/django/utils/encoding.py",
> line 35, in smart_unicode
> return force_unicode(s, encoding, strings_only, errors)
> File "/usr/lib/python2.5/site-packages/django/utils/encoding.py",
> line 70, in force_unicode
> raise DjangoUnicodeDecodeError(s, *e.args)
> DjangoUnicodeDecodeError: 'utf8' codec can't decode byte 0xff in
> position 0: unexpected code byte. You passed in '\xff\xd8\xff...
> [...]
>
> Any clue on how to fix this. Should I be doing a special encoding/
> compression before placing the image file into the cache?
>
See tickets #9180 and #5589 for related reports and proposed workarounds/fixes
when using the memcache backend.
Regards,
--
Ramiro Morales
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