Hello, I would like to change the view so that the link retrieves more of the detailed information from the same model publication, but I haven't figured out how to change the view to respond either to a new search and/or to more detailed information about the item found. The link can go to a new page or refresh on the current search.html page. See http://dpaste.com/106410/ for the html and the view.
The URL is: urlpatterns = patterns('mysite.fsafety.views.', (r'^$', 'index'), (r'^search/$', 'search'), ) Thank you for any help. Bob --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---