Thanks Bruno request.get_full_path() is enough for me .

Best regards

09 Ocak 2009 Cuma 18:31 tarihinde bruno desthuilliers <
bruno.desthuilli...@gmail.com> yazdı:

>
>
>
> On 9 jan, 17:06, "burcu hamamcıoğlu" <borco...@gmail.com> wrote:
> > Hi everybody,
> >
> > do you know how can i get request url in views.py.
> >
> > My url pattern is like
> (r'^wp/rmain2\.aspx','DisplayPacketApplications2'),
> > But my link is like :
> http://wap2.cepoyun.com/wp/rmain2.aspx?pid=194&w=280jhjh
> >
> > when i use 'PATH_INFO' i olnly get 'wp/rmain2\.aspx' of the link. How can
> i
> > get the full link above ?
>
> request.get_full_path() will give you the path + the querystring.
>
>
> http://docs.djangoproject.com/en/dev/ref/request-response/#django.http.HttpRequest.get_full_path
>
> But if what you want is to get the 'pid' and 'w' arguments of the
> querystring, it might be simpler to use request.GET, ie:
>
> def youview(request):
>   pid = request.GET.get(pid)
>   w = request.GET.get(w)
>   # you code here
>
> Have a look at the FineManuel(tm) for more about the HttpRequest
> object:
> http://docs.djangoproject.com/en/dev/ref/request-response/
>
> >
>

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