I tried that option and received this error:
Cannot resolve keyword 'institution_institution' into field
However, I think I may have it. I used this statement:
qset2 = (
Q(institution__icontains=queryr)
)
resultsi = Institution.objects.filter(qset2).distinct()
for id in resultsi:
resultsii=Researchproject.objects.filter(institution=id)
And am able to get the results in the template. It just makes for
more coding, however, in the view. It would be easier to have all the
code in the qset and not have to add another qset2.
On Mar 3, 1:01 pm, Tim <timster...@gmail.com> wrote:
> If you want to look up an Institution using the Project model, you
> should be able to use "institution__institution__icontains"
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to
django-users+unsubscr...@googlegroups.com
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---
