Thanks for your responses, they helped :)
In the code below:
ret['b'] = State.objects.all()
print 'ret: %' % ret
try:
serialized = encoder.JSONEncoder().encode(ret)
except Exception, e:
print 'exception: %s' % e
I was doing the following mistake - I wanted to serialize query set in a
dictionary directly, and the exception was thrown, I think because
encoder.JSONEncoder() can't encode a QuerySet.
While using code like this:
ret = State.objects.all()
json_serializer = serializers.get_serializer("json")()
serialized_model = json_serializer.serialize(ret, ensure_ascii = False)
ret_val['b'] = serialized_model
serialized = encoder.JSONEncoder().encode(ret_val)
then it doesn't throw exception, but code above just creates a
serialized dicionary of serialized model, so when I try to decode it
with JSON parser on a page, i get a dictionary of strings. I can create
a JSON response manually by:
serialized = '{"b":%s}'% serialized_model
but it's a little annoying while serializing a few models.
Is there any way to serialize dictionary of QuerySets without creating
json response manually?
Regards,
Marek
> You know what's weird? I've used simplejson.dumps() plenty of times
> in my own code... not sure why that one just slipped out of my
> memory. I should just stop responding to things :-)
>
> Anyway, since you're serializing a model, you *should* be using your
> originally posted method. Use the way Marek said for anything other
> than models (of course, the object has to be serializable.)
>
> If that doesn't work, post the full (relevant) code.
>
> -Jeff
>
> On Mar 5, 7:01 am, Marek Wawrzyczek <[email protected]> wrote:
>
>> > Thomas Guettler wrote:
>> >
>>
>>> > > Jeff FW schrieb:
>>>
>> >
>>
>>>> > >> The serializers are for serializing querysets/models. I'm surprised
>>>> > >> you're not getting an error message there--are you catching all
>>>> > >> exceptions?
>>>>
>> >
>>
>>>> > >> What you want is in django.utils.simplejson:
>>>>
>> >
>>
>>>> > >> from django.utils.simplejson import encoder
>>>> > >> encoder.JSONEncoder().encode(ret)
>>>>
>> >
>>
>>> > > Or this:
>>>
>> >
>>
>>>>>> > >>>> from django.utils import simplejson
>>>>>> > >>>> simplejson.dumps(...)
>>>>>>
>> >
>>
>>> > > But unfortunately this does not encode datetime objects.
>>>
>> >
>>
>>> > > Thomas
>>>
>> >
>> > Thanks for your responses. Now when I try
>> >
>> > ret = { }
>> > ret['a'] = 'b'
>> > serialized = encoder.JSONEncoder().encode(ret)
>> > print serialized
>> >
>> > then It works.
>> >
>> > But now I have another problem. I have a class "State":
>> >
>> > class State(models.Model):
>> > state = models.CharField(max_length = 30)
>> >
>> > def __unicode__(self):
>> > return self.state
>> >
>> > Throutht the admin page I create a state called "Slaskie".
>> > Then the code :
>> >
>> > ret['b'] = State.objects.all()
>> > print 'ret: %' % ret
>> > try:
>> > serialized = encoder.JSONEncoder().encode(ret)
>> > except Exception, e:
>> > print 'exception: %s' % e
>> >
>> > returns the output:
>> >
>> > {'b': [<State: Slaskie>]}
>> > [<State: Slaskie>] is not JSON serializable
>> >
>> > At the
>> > pagehttp://docs.djangoproject.com/en/dev/topics/serialization/#id2there's
>> > written something about unicode and lazy translation. I tried to use
>> >
>> > le = LazyEncoder() #lazy encoder is a given class from the
>> > link above
>> > serialized = le.encode(ret)
>> >
>> > and then the exception was:
>> > Circular reference detected
>> >
>> > when I tried
>> >
>> > le = LazyEncoder (ensure_ascii = False)
>> >
>> > the exception was the same:
>> > Circular reference detected
>> >
>> > What's going on with this lazy translation and unicode ? How can I
>> > serialize the data correctly ?
>> >
>> > Regards,
>> > Marek
>>
> >
>
>
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