First, I want to thank you for sticking with me and helping me through
this. I've learned a lot, but unfortunately made no progress yet.
I read the links you sent and ended up trying this in forms.py:
from django.contrib import admin
class ProjectAdmin(admin.ModelAdmin):
formfield_overrides = {
models.CommaSeparatedIntegerField: {'widget':
forms.SelectMultiple},
}
but I get an error " 'module' object has no attribute 'ModelAdmin' "
(I verified this from python manage.py shell)
My guess is I'm using an older django distribution. Unfortunately,
this isn't something I can update since it's on a server I have
limited access to.
Before taking this tack, I was trying something like this (again, in
forms.py)
(
http://docs.djangoproject.com/en/dev/topics/forms/modelforms/#overriding-the-default-field-types
)
class ProjectForm(forms.ModelForm):
stains = forms.CommaSeparatedIntegerField
(widget=forms.SelectMultiple(choices=STAINS_CHOICES))
class Meta:
model = Project
...with this I get a strange error:
ViewDoesNotExist at /projectprofiler/admin/projects/project/504/
Tried logout_view in module projectprofiler.projects.views. Error was:
'module' object has no attribute 'CommaSeparatedIntegerField'
Request Method: GET
Request URL:
http://imageweb.broad.mit.edu:8081/projectprofiler/admin/projects/project/504/
Exception Type: ViewDoesNotExist
Exception Value: Tried logout_view in module
projectprofiler.projects.views. Error was: 'module' object has no
attribute 'CommaSeparatedIntegerField'
Exception Location: /imaging/analysis/People/imageweb/python-packages/
django/core/urlresolvers.py in _get_callback, line 184
...
In template /home/radon01/afraser/projectprofiler/templates/admin/
base.html, error at line 28
28 <a href="{% url projectprofiler.admin.views.main.password_change
%}">{% trans 'Change password' %}</a>
...I can't figure out what the password_change view as to do with the
commaseparatedintegerfield.
Thanks again :]
Adam
On Mar 26, 11:39 am, Brian Neal <bgn...@gmail.com> wrote:
> On Mar 26, 9:59 am, Adam Fraser <adam.n.fra...@gmail.com> wrote:
>
> > hrm, I think I'm _finally_ starting to understand how django is meant
> > to be used.
>
> > Question: Why can't I just specify the widget used by a particular
> > field from my model in the admin interface.
>
> > stains = models.CommaSeparatedIntegerField(widget=SelectMultiple
> > (choices=STAIN_CHOICES))
>
> > ...or can I? You suggested something like this earlier only referred
> > to forms.CommaSeparatedIntegerField rather than
> > models.CommaSeparatedIntegerField.
>
> > hrm
>
> Models are simply models. They don't really say much about forms. What
> the admin application does is to make some default choices about how
> to display your model in the admin interface. It automatically builds
> the form to edit your model using some very reasonable defaults. If
> you aren't happy with those choices, you can provide the form that the
> admin should use instead of the default one. In your form, you are
> free to use different widgets for your fields and/or provide custom
> behavior.
>
> The docs describe how to provide your own form to the admin
> here:http://docs.djangoproject.com/en/dev/ref/contrib/admin/#form
>
> You simply provide an attribute on your ModelAdmin called 'form', set
> equal to the form class you want the admin to use. This form class
> should inherit from ModelForm. You can then customize the widgets and
> behavior anyway you would like.
>
> ModelForms are discussed
> here:http://docs.djangoproject.com/en/dev/topics/forms/modelforms/#topics-...
>
> Overriding the default field type for a field on a ModelForm is a bit
> further
> down:http://docs.djangoproject.com/en/dev/topics/forms/modelforms/#overrid...
>
> But before you read all that, make sure you understand forms in
> Django, in
> general:http://docs.djangoproject.com/en/dev/topics/forms/#topics-forms-index
>
> Armed with that info, you should be able to make a custom form for the
> admin to use. Good luck.
>
> BN
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